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-0.01x^2+1.18x+3=0
a = -0.01; b = 1.18; c = +3;
Δ = b2-4ac
Δ = 1.182-4·(-0.01)·3
Δ = 1.5124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.18)-\sqrt{1.5124}}{2*-0.01}=\frac{-1.18-\sqrt{1.5124}}{-0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.18)+\sqrt{1.5124}}{2*-0.01}=\frac{-1.18+\sqrt{1.5124}}{-0.02} $
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